Answer :
namely, if the consumption in 1974 was "x" or the 100%, 4300 is 54.7% extra of that, so 4300 is really 100%+54.7%, or 154.7%, now, what is "x" then?
well [tex]\bf \begin{array}{ccllll} amount&\%\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ 4300&154.7\\ x&100 \end{array}\implies \cfrac{4300}{x}=\cfrac{154.7}{100}[/tex]
solve for "x"
well [tex]\bf \begin{array}{ccllll} amount&\%\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ 4300&154.7\\ x&100 \end{array}\implies \cfrac{4300}{x}=\cfrac{154.7}{100}[/tex]
solve for "x"