Answer :
The chemical reaction is written as:
Mg + 2HNO3 = Mg(NO3)2 + H2
We use this reaction and the amounts given to calculate the theoretical yield of the reactants. Then, we can calculate for the percent yield We do as follows:
20 g Mg (1 mol / 24.31 g) ( 1 mol H2 / 1 mol Mg ) (2.02 g / 1 mol ) = 1.66 g H2 theoretical
Therefore,
Percent yield = 1.66 / 1.7 x100 = 97.8%
Mg + 2HNO3 = Mg(NO3)2 + H2
We use this reaction and the amounts given to calculate the theoretical yield of the reactants. Then, we can calculate for the percent yield We do as follows:
20 g Mg (1 mol / 24.31 g) ( 1 mol H2 / 1 mol Mg ) (2.02 g / 1 mol ) = 1.66 g H2 theoretical
Therefore,
Percent yield = 1.66 / 1.7 x100 = 97.8%