Answer :
1. Consider the quadratic equation [tex]4 x^{2}+5x+3=0 [/tex]
a=4, b=5, c=3
the discriminant [tex]D= b^{2}-4ac= 5^{2}-4*4*3=25-48=-23[/tex] <0
D<0 so there are no real solutions to the equation.
a=4, b=5, c=3
the discriminant [tex]D= b^{2}-4ac= 5^{2}-4*4*3=25-48=-23[/tex] <0
D<0 so there are no real solutions to the equation.