Answer :
Assuming that these cubes are numbered as standard dice are:
P(>2B and (2n-1)G)=P(>2B)*P((2n-1)G)
P(>2B and (2n-1)G)=(4/6)(3/6)=12/36=1/3
P(>2B and (2n-1)G)=P(>2B)*P((2n-1)G)
P(>2B and (2n-1)G)=(4/6)(3/6)=12/36=1/3