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To construct a battery with a current of 6 A, you would connect six 1 A cells
A. in parallel.
B. to a ground.
C. in series-parallel.
D. in series.

I chose "D" but the answer was actually "A". Can someone better explain that to me?

Answer :

erikyvan13
A. in parallel.,D. in series.

Answer:

A. in parallel.

Explanation:

In the series circuit, the current is the same for all of the elements in the circuit. This means that current in a resistor is the same as in every other resistor

Mathematically,

I = [tex]I_{1}[/tex] = [tex]I_{2}[/tex] = ... = [tex]I_{n}[/tex]

In the parallel circuit, the total current is the sum of the currents through the individual components

Mathematically,

[tex]I_{total}[/tex]= [tex]I_{1}[/tex] + [tex]I_{2}[/tex] + ... + [tex]I_{n}[/tex]

For the series circuit, connecting six 1 A cells yields

I = [tex]I_{1}[/tex] = [tex]I_{2}[/tex] = [tex]I_{3}[/tex] = [tex]I_{4}[/tex] = [tex]I_{5}[/tex] = [tex]I_{6}[/tex] = 1 A

For the parallel circuit, connecting six 1 A cells yields

[tex]I_{total}[/tex] = [tex]I_{1}[/tex] + [tex]I_{2}[/tex] + [tex]I_{3}[/tex] + [tex]I_{4}[/tex] + [tex]I_{5}[/tex] + [tex]I_{6}[/tex] = (1 + 1 + 1 + 1 + 1 +1) A

[tex]I_{total}[/tex] = 6 A

It therefore follows that the answer is option A. in parallel.

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