Answer :
I am assuming you in your question mean 4x^2-8x+8-x^2+2x-4-3x^2+_=4
4x^2-x^2-3x^2=0 so you get
-8x+8+2x-4+_=4
-6x+4+_=4
so _=6x
4x^2-x^2-3x^2=0 so you get
-8x+8+2x-4+_=4
-6x+4+_=4
so _=6x
Answer:
+6x
Step-by-step explanation:
Given is an equation with a missing term as follows:
[tex]4x^2 -8x + 8 -x^2 + 2x -4 - 3x^2 +_ = 4[/tex]
Simplify by grouping the like terms as follows:
[tex](4x^2- 3x^2- x^2) +(-8x + 2x )+( 8-4) +_ = 4\\-6x+4+_ =4\\-6x+_=0[/tex]
Thus missing term must be
+6x