Answer :
A=address labels
F=flyers
50A+75F=21.25.........(1)
100A+50F=27.50.......(2)
Solve for A and F
2(1)-(2)
100F=15 => F=0.15
substitute in (1)
50A+11.25=21.25 =>
A=10/50=0.20
So an address label costs $0.20, and a flyer costs 0.15, one of each they cost 0.35.
F=flyers
50A+75F=21.25.........(1)
100A+50F=27.50.......(2)
Solve for A and F
2(1)-(2)
100F=15 => F=0.15
substitute in (1)
50A+11.25=21.25 =>
A=10/50=0.20
So an address label costs $0.20, and a flyer costs 0.15, one of each they cost 0.35.