Answer :
the answer
to find the area of this parallelogram, first, we must find the value of its length and width
The area can be found with the formula A = L x W
L = length
W= width
according to the image, the dimensions are L =UT and W= UR
vector UT = (6,2) and vector UT= (-4,4)
so L= length of vector UT = sqrt (6²+2²)=sqrt(40) =2 √10
and W= length of vector UR= sqrt(4²+4²)=sqrt(32) =4√2
to find the area of this parallelogram, first, we must find the value of its length and width
The area can be found with the formula A = L x W
L = length
W= width
according to the image, the dimensions are L =UT and W= UR
vector UT = (6,2) and vector UT= (-4,4)
so L= length of vector UT = sqrt (6²+2²)=sqrt(40) =2 √10
and W= length of vector UR= sqrt(4²+4²)=sqrt(32) =4√2