Answer :
Answer:
It decreases as the concentration of products decreases.
It increases as the concentration of products increases.
Explanation:
the equilibrium reaction is
[tex]N_{2}(g)+O_{2}(g)<==>2NO(g)[/tex]
As per equilibrium,
a) there will be no effect of pressure change on the equilibrium as the number of gaseous molecules are same on both the side of reaction.
b) there will be no effect of addition of inert gas on the equilibrium as the number of gaseous molecules are same on both the side of reaction.
c) the reverse reaction rate can be increased by
i) decreasing the concentration of reactants
ii) increasing the concentration of products
As the chemical reaction proceeds towards equilibrium, the rate of the reverse reaction:
- Decreases as the concentration of products decreases.
- Increases as the concentration of products increases.
What is a reversible reaction?
A reversible reaction can be defined as a chemical reaction that is capable of reforming (reproducing) it's reactants from the resulting formation of products.
This ultimately implies that, a reversible reaction refers to a chemical reaction that is in equilibrium because both the forward and reverse paths happen at the same rate (simultaneously).
The balanced chemical equation for the reaction of nitrogen gas and oxygen gas is:
[tex]N_2(g) + O_2(g) \rightleftharpoons 2NO(g)[/tex]
In conclusion, as the above chemical reaction proceeds towards equilibrium, the rate of the reverse reaction:
- Decreases as the concentration of products decreases.
- Increases as the concentration of products increases.
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