Answer :
The answer is A. 1350
(ALL NUMBERS Except the grams is given from the equation)
18.21mol HNO3/1 * 1mol MgN206/2mol/ 2mol HNO3 * (molar mass-->)148.30 MgN206/ 1mol MgN2O6
You multiply 18.21HNO3* 1mol MgN2O6 * 148.30MgN2O6
Then divide it by the 2mol HNO3 to get 1350
(ALL NUMBERS Except the grams is given from the equation)
18.21mol HNO3/1 * 1mol MgN206/2mol/ 2mol HNO3 * (molar mass-->)148.30 MgN206/ 1mol MgN2O6
You multiply 18.21HNO3* 1mol MgN2O6 * 148.30MgN2O6
Then divide it by the 2mol HNO3 to get 1350