subeenuddin
Answered

Andrew deposited $500 in a savings account that offers an interest rate of 6.5%, compounded continuously.
Andrew's initial deposit will grow to $543 in ___
months.

Answer :

Aliwohaish12
The formula is
A=pe^(r×t/12)
A future value 543
P present value 500
R interest rate 0.065
E constant
T time t ( in months)

Solve the formula for t
T/12=[log (A/p)÷log (e)]÷r
T/12=(log(543÷500)÷log(e))÷0.065
T/12=1.3
T=1.3×12
T=15 months

Answer:

Time in months ≈ 16 months

Step-by-step explanation:

Principal Amount = $500

Interest Rate = 6.5%

Amount = $543

n = Number of times the interest is compounded

⇒ n = 12 ( because given that the interest is compounded continuously)

We need to calculate Time in months :

[tex]Amount=Principal\times (1+\frac{Rate}{100\times n})^{Time\times n}\\\\\implies 543 = 500\times (1+\frac{6.5}{100\times 12})^{12\times Time}\\\\\implies 1.086=(1.0054)^{12\times Time}\\\\\text{Taking log on both the sides}\\\\\implies \log1.086 = 12\times Time \times \log 1.0054\\\\\implies 12 \times Time=15.32\\\\\implies Time = 1.28\:\:years[/tex]

So, Time in months = 1.28 × 12

                                  ≈ 16 months

Other Questions