Answer :
Inverse works in this way:
y = 1/9x + 2,
you should swap the places of x and y and find y again, in this case it will be
x = 1/9y + 2 => x-2 = 1/9y => (x-2) * 9y = 1 => 9y = 1/(x-2)
and finally we got y = [tex] \frac{1}{(x-2)*9} [/tex]
y = 1/9x + 2,
you should swap the places of x and y and find y again, in this case it will be
x = 1/9y + 2 => x-2 = 1/9y => (x-2) * 9y = 1 => 9y = 1/(x-2)
and finally we got y = [tex] \frac{1}{(x-2)*9} [/tex]