The sequence forms a Geometric sequence as the rule to obtain the value for the next term is by ratio
Term 1: 1000
Term 2: 200
Term 3: 40
From term 1 to term 2, there's a decrease by [tex] \frac{1}{5} [/tex]
From term 2 to term 3, there's a decrease also by [tex] \frac{1}{5} [/tex]
The rule to find the [tex]n^{th} [/tex] term in a sequence is
[tex]n^{th}=a r^{n-1} [/tex], where [tex]a[/tex] is the first term in the sequence and [tex]r[/tex] is the ratio
So, the formula for the sequence in question is
[tex]n_{th} [/tex] term = [tex]1000( \frac{1}{5} ^{n-1} )[/tex]
The sequence is a divergent one. We can always find the value of the next term by dividing the previous term by 5 and if we do that, the value of the next term will get closer to 'zero' but never actually equal to zero.
We can find a partial sum of the sequence using the formula
[tex]S_{∞} = \frac{a}{1-r} [/tex] for -1<r<1
Substituting [tex]a=1000[/tex] and [tex]r= \frac{1}{5} [/tex] we have
[tex] S_{∞} [/tex] = [tex] \frac{1000}{1- \frac{1}{5} } [/tex] = 1250
Hence, the correct option is option number 1