Answer :
((2f^4)^2*f^3)/(6f^9)
pertinent rules of exponents:
(a^b)^c=a^(b*c), (a^b)(a^c)=a^(b+c), and (a^b)/(a^c)=a^(b-c) so
(2f^(4*2)*f^3)/(6f^9)
(2f^8*f^3)/(6f^9)
(2f^(8+3))/(6f^9)
(2f^11)/(6f^9)
(2/6)(f^11/f^9)
(1/3)(f^(11-9)
(1/3)(f^2)
(f^2)/3
pertinent rules of exponents:
(a^b)^c=a^(b*c), (a^b)(a^c)=a^(b+c), and (a^b)/(a^c)=a^(b-c) so
(2f^(4*2)*f^3)/(6f^9)
(2f^8*f^3)/(6f^9)
(2f^(8+3))/(6f^9)
(2f^11)/(6f^9)
(2/6)(f^11/f^9)
(1/3)(f^(11-9)
(1/3)(f^2)
(f^2)/3