Answer :
Answer:
Using the trigonometric identity \( \sin(x) = \cos(90° - x) \), you can express \( \cos(68°) \) in terms of sine:
\[ \cos(68°) = \sin(90° - 68°) \]
Simplifying, you get:
\[ \cos(68°) = \sin(22°) \]
Answer:
Using the trigonometric identity \( \sin(x) = \cos(90° - x) \), you can express \( \cos(68°) \) in terms of sine:
\[ \cos(68°) = \sin(90° - 68°) \]
Simplifying, you get:
\[ \cos(68°) = \sin(22°) \]