Answer :
the differnce of 2 perfect cubes
remember
a³-b³=(a-b)(a²+ab+b²)
so
[tex](x^2)^3-(3)^3=(x^2-3)(x^2+3x+9)[/tex]
remember
a³-b³=(a-b)(a²+ab+b²)
so
[tex](x^2)^3-(3)^3=(x^2-3)(x^2+3x+9)[/tex]