Answer :
[tex]P=2l+2w[/tex]
[tex]P=2(\frac{x}{6}-1)+2(x)[/tex]
[tex]P=\frac{2x}{6}-2+2x[/tex]
[tex]P=\frac{x}{3}-2+2x[/tex]
[tex]P=2\frac{1}{3}x-2[/tex]
[tex]P=2(\frac{x}{6}-1)+2(x)[/tex]
[tex]P=\frac{2x}{6}-2+2x[/tex]
[tex]P=\frac{x}{3}-2+2x[/tex]
[tex]P=2\frac{1}{3}x-2[/tex]
Answer:
Perimeter =[tex]\frac{7}{3}x-2[/tex]
Step-by-step explanation:
The length of a rectangle is one unit shorter than one-sixth of the width, x
LEts x be the width of the rectangle
Length is 1 unit shorter than 1/6 of width
[tex]Length = \frac{1}{6} x-1[/tex]
Perimeter of the rectangle = 2(length ) + 2(width)
Replace length and width
Perimeter =[tex]2(\frac{1}{6} x-1)+2x[/tex]
Simplify it
Perimeter =[tex]\frac{1}{3} x-2+2x[/tex]
[tex]\frac{1}{3} x+2x=\frac{1}{3}x+\frac{6}{3} x=\frac{7}{3}x[/tex]
Perimeter =[tex]\frac{7}{3}x-2[/tex]