Answer :

SchwarzschildRadius
So,

[tex](q^7)(q)(q^{-9})(9^-3)[/tex]

Multiply compatible exponents.
[tex](q^8)(q^{-9})(9^-3)[/tex]
[tex](q^{-1})(9^-3)[/tex]

Simplify.
[tex]\frac{9^{-3}}{q} [/tex]
[tex]\frac{1}{729q} [/tex]
isistheicecube

Answer:

So,

(q^7)(q)(q^{-9})(9^-3)

Multiply compatible exponents.

(q^8)(q^{-9})(9^-3)

(q^{-1})(9^-3)

Simplify.

\frac{9^{-3}}{q}  

\frac{1}{729q}

Step-by-step explanation:

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