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During fuel burn, the vertically launched terrier-sandhawk rocket had an acceleration of 300 m/s2 (about 30 times free-fall acceleration called 30 g). the fuel burned for 8.0 s . find the height of the terrier-sandhawk rocket at the end of fuel burn.

Answer :

Vertical acceleration = 300 m/s²
Initial vertical velocity  = 0
Time of flight  = 8.0 s

Calculate the height after 8 s.
h = (1/2)*(300 m/s²)*(8.0 s)² = 9600 m

Answer: 9600 m

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