Answer :
2 and 8 have fixed places - 2 in the ten-thousands place and and 8 in the ones place (number must be even).
There remaining 3 numbers left can be arranged in [tex]3!=6[/tex] ways.
So, there are 6 different ways.
There remaining 3 numbers left can be arranged in [tex]3!=6[/tex] ways.
So, there are 6 different ways.