Answer :

[tex]4\ to\ the\ second\ power=4^2=4\cdot4=16\\\\3\ to\ the\ 3rd\ power=3^3=3\cdot3\cdot3=9\cdot3=27\\\\4\ to\ the\ second\ power\ plus\ 3\ to\ the\ 3rd\ power:\\\\4^2+3^3=16+27=\huge\boxed{43}[/tex]
trueangel12310
4 to the second power: 4²
3 to the third power: 3³
4*4=16
3*3*3=27
16+27=43

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