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Let z be a random variable with a standard normal distribution. find the indicated probability. (round your answer to four decimal places.) p(z ≤ −0.16)

Answer :

barnuts

We are asked to find for the probability when z is less than or equal to -0.16. We can solve this by looking at the standard probability distribution tables. From the tables, the p value using left tailed test is:

P = 0.4364 = 43.64%

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