Answer :
Given
[tex] \frac{ \frac{3}{x-1} -4}{2- \frac{2}{x-1} } = \frac{ \frac{3-4(x-1)}{x-1} }{ \frac{2(x-1)-2}{x-1} } \\ \\ = \frac{3-4x+4}{2x-2-2} = \frac{7-4x}{2x-4} \\ \\ = \frac{-4x+7}{2(x-2)} [/tex]
[tex] \frac{ \frac{3}{x-1} -4}{2- \frac{2}{x-1} } = \frac{ \frac{3-4(x-1)}{x-1} }{ \frac{2(x-1)-2}{x-1} } \\ \\ = \frac{3-4x+4}{2x-2-2} = \frac{7-4x}{2x-4} \\ \\ = \frac{-4x+7}{2(x-2)} [/tex]