Answer :

Kalahira
given:
 y= x^2-2x
 u=2x+1
   y = x^2 -2
   dy/dx = 2x
    u = 2x + 1
  du/dx = 2
   dx/du = 1/2
    dy/du = dy/dx * dx/du
  dy/du = 3x * 1/2
  dy/du = 3x/2
   Answer: dy/du = 3x/2

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