Answer :
[tex] \frac{3y}{y^2+7y+10} + \frac{2}{y+2} \\ \\ = \frac{3y}{(y+2)(y+5)} + \frac{2}{y+2} \\ \\ = \frac{3y}{(y+2)(y+5)} + \frac{2(y+5)}{(y+2)(y+5)} \\ \\ = \frac{3y+2(y+5)}{(y+2)(y+5)} = \frac{3y+2y+10}{(y+2)(y+5)} \\ \\ = \frac{5y+10}{(y+2)(y+5)} = \frac{5(y+2)}{(y+2)(y+5)} \\ \\ = \frac{5}{y+5} [/tex]