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Can someone please help?
A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle of 20° east of north. Identify the ship's vector, the water current's vector, and the vector representing the ship's actual motion.

Answer :

carlosego
The first thing you should do is write each speed in vector form.
 v1: vector water velocity
 v2: vector boat speed with respect to water
 writing the vectors we have
 v1 = (5 * COS (20 * (PI () / 180)) i) + (5 * SENO (20 * (PI () / 180)) j)
 v2 = (30 * COS (30 * (PI () / 180)) i) - (30 * SENO (30 * (PI () / 180)) j)
 The vector representing the ship's current motion will be given by the sum of vectors v1 and v2
 v1 + v2 = (30.67922522 i) + (15.67922522 j)

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