Answer:
[tex]5\sqrt{2}[/tex] units.
Step-by-step explanation:
We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.
We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.
[tex]\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2[/tex]
Substituting our given values in above equation we will get,
[tex]\text{Hypotenuse}^2=5^2+5^2[/tex]
[tex]\text{Hypotenuse}^2=25+25[/tex]
[tex]\text{Hypotenuse}^2=50[/tex]
Upon taking square root of both sides of our equation we will get,
[tex]\text{Hypotenuse}=\sqrt{50}[/tex]
[tex]\text{Hypotenuse}=\sqrt{25*2}[/tex]
[tex]\text{Hypotenuse}=5\sqrt{2}[/tex]
Therefore, the length of hypotenuse of triangle ABC is [tex]5\sqrt{2}[/tex] units.
