Answer :
y^x:y^x = 1 because a:a=1 for every a
but y^x:y^x=y^(x-x)=y^0
Ex: 2^3:2^2=2^(3-2)=2
8:4=2
⇒ y^0=1
but y^x:y^x=y^(x-x)=y^0
Ex: 2^3:2^2=2^(3-2)=2
8:4=2
⇒ y^0=1