Answer :
[tex]\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\quad
\begin{cases}
r=radius\\
-----\\
V=1761.1
\end{cases}\implies 1761.1=\cfrac{4\pi r^3}{3}
\\\\\\
3(1761.1)=4\pi r^3\implies \cfrac{3(1761.1)}{4\pi }=r^3\implies \sqrt[3]{\cfrac{3(1761.1)}{4\pi }}=r[/tex]