Answer :
If the image is centered at the origin you can divide the terms of the image from the preimage to find the scale or ratio at which it was dilated. In this case, you will use the points of A because the point b does not matter in this case.
[tex] \frac{-6}{-4} = 1.5 [/tex] and [tex] \frac{9}{6} = 1.5[/tex] so the image is dilated by a scale of 1.5
now that we know the scale we multiply the points of B by the scale to get the image. 1*1.5 = 1.5 and 4*1.5 = 6 so the image for B is (1.5, 6)
[tex] \frac{-6}{-4} = 1.5 [/tex] and [tex] \frac{9}{6} = 1.5[/tex] so the image is dilated by a scale of 1.5
now that we know the scale we multiply the points of B by the scale to get the image. 1*1.5 = 1.5 and 4*1.5 = 6 so the image for B is (1.5, 6)
The image of point B is B'(1.5,6).and this can be determined by finding the dilation factor and then multiplying point B by the dilation factor.
Given :
- Segment AB has endpoints A(–4, 6) and B(1, 4).
- After a dilation, centered at the origin, the image of A is (–6, 9).
In order to determine the image of point B, first, determine the dilation factor. let 'x' be the dilation factor, then:
[tex]-4\times x = -6[/tex]
[tex]x = \dfrac{3}{2}[/tex]
Now, after dilation the point B becomes:
[tex]\rm B(1,4)\to B'(1\times \dfrac{3}{2},4\times \dfrac{3}{2})[/tex]
Simplify the above expression.
[tex]\rm B'\left(\dfrac{3}{2},6\right) = B'(1.5,6)[/tex]
The image of point B is B'(1.5,6).
For more information, refer to the link given below:
https://brainly.com/question/19347268