Answer :
---
y(t) = a*e^(kt)
---
now:
130 mg
---
one hour from intake:
130 * (1 - 0.11) = 115.7 mg
---
y(1) = 115.7 = 130*e^(k(1))
115.7 = 130*e^k
115.7/130 = e^k
ln( 115.7/130 ) = ln( e^k )
ln( 115.7/130 ) = k
k = -0.1165338
---
three hours from intake:
y(3) = 130*e^(3k)
y(3) = 91.64597
---
answer:
three hours after drinking a cup of coffee, 91.6 mg of caffeine will remain in the body
y(t) = a*e^(kt)
---
now:
130 mg
---
one hour from intake:
130 * (1 - 0.11) = 115.7 mg
---
y(1) = 115.7 = 130*e^(k(1))
115.7 = 130*e^k
115.7/130 = e^k
ln( 115.7/130 ) = ln( e^k )
ln( 115.7/130 ) = k
k = -0.1165338
---
three hours from intake:
y(3) = 130*e^(3k)
y(3) = 91.64597
---
answer:
three hours after drinking a cup of coffee, 91.6 mg of caffeine will remain in the body