Answer :
Simply substitute x by its value:
1)
f(x) = x + 4 ; x = 3p f(x) = x + 4 ;
f(3p) = 3p + 4 f(1) = 1 + 4
f(1) = 5
x = 3p (1,5)
y = 3p + 4
2) g(x) = 3(x-2) g(x) = 3(x-2)
g(x) = 6 g(1) = 3(1-2)
g(1) = 3 - 6
6 = 3x - 6 g(1) = -3
6+6 = 3x (1,-3)
12 = 3x
x = 4
g(4) = 3(4-2)
g(4) = 12 - 6
g(4) = 6
x = 4
y = 6
1)
f(x) = x + 4 ; x = 3p f(x) = x + 4 ;
f(3p) = 3p + 4 f(1) = 1 + 4
f(1) = 5
x = 3p (1,5)
y = 3p + 4
2) g(x) = 3(x-2) g(x) = 3(x-2)
g(x) = 6 g(1) = 3(1-2)
g(1) = 3 - 6
6 = 3x - 6 g(1) = -3
6+6 = 3x (1,-3)
12 = 3x
x = 4
g(4) = 3(4-2)
g(4) = 12 - 6
g(4) = 6
x = 4
y = 6