Answer :
a] Brenda's amount after 6 years will be given by:
FV=P(1+r/100*n)^nt
where
P=principle amount
r=rate
n=number of terms
t=time
thus
FV=5000(1+3.4/(2*100))^(2*6)
FV=5000(1.017)^12
FV=$6120.987
The amount of 6 years will be $6120.987
b. The rate at which Luke invested will be given by:
FV=p(1+r/100)^n
FV=$6250
p=5000
n=6 years
r=?
6250=5000(1+r/100)^6
solving for r we get
1.25=(1+r/100)^6
1.037891=1+r/100
0.037891=r/100
r=3.7891%
FV=P(1+r/100*n)^nt
where
P=principle amount
r=rate
n=number of terms
t=time
thus
FV=5000(1+3.4/(2*100))^(2*6)
FV=5000(1.017)^12
FV=$6120.987
The amount of 6 years will be $6120.987
b. The rate at which Luke invested will be given by:
FV=p(1+r/100)^n
FV=$6250
p=5000
n=6 years
r=?
6250=5000(1+r/100)^6
solving for r we get
1.25=(1+r/100)^6
1.037891=1+r/100
0.037891=r/100
r=3.7891%