Answer:
The correct option is B.
Step-by-step explanation:
The given vertices are (-4,2),(1,2),(1,-3) and (-4,-3).
Plot these point on a coordinate plate. From the graph it is noticed that the given quadrilateral is a square.
Distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Use distance formula to find the side length.
[tex]AB=\sqrt{(1-(-4))^2+(2-2)^2}=\sqrt{5^2}=5[/tex]
[tex]BC=\sqrt{(1-1)^2+(-3-2)^2}=\sqrt{(25}=5[/tex]
Since both consecutive sides are equal therefore it is a square.
Area of a square is
[tex]A=a^2[/tex]
Where, a is side length.
The side length of the square is 5. So, area of ABCD is
[tex]A=(5)^2[/tex]
[tex]A=25[/tex]
Therefore the area of quadrilateral is 25 units square. Option B is correct.
