In an electric field, 0.90 joule of work is required to bring 0.45 coulomb of charge from point a to point
b. what is the electric potential difference between points a and b?

Answer :

skyluke89
The difference in electric potential energy between the two points is
[tex]\Delta U = q \Delta V[/tex]
where q is the magnitude of the charge and [tex]\Delta V[/tex] is the electric potential difference.

But for energy conservation, the difference in electric potential energy [tex]\Delta U[/tex] between the two points is equal to the work done to move the charge between A and B:
[tex]W=\Delta U[/tex]
so we have
[tex]W=q \Delta V[/tex]

and by substituting the numbers of the problem, we find the value of [tex]\Delta V[/tex]:
[tex]\Delta V = \frac{W}{q}= \frac{0.90 J}{0.45 C}=2 V [/tex]

Other Questions