Answer :
The moles of ammonia in 1.20 x10^25 molecules of ammonia is calculated as follows
by use of Avogadro constant
1moles = 6.02 x10^23
what about 1.20 x10^25 moles
by use of cross multiplication
= 1 mole x ( 1.20 x10^25) /( 6.02 x10^23) = 19.93 moles
by use of Avogadro constant
1moles = 6.02 x10^23
what about 1.20 x10^25 moles
by use of cross multiplication
= 1 mole x ( 1.20 x10^25) /( 6.02 x10^23) = 19.93 moles