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the height of a triangle is 5m less than its base. the area of the triangle is 42m^2
what is the length of the base
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__ m

Answer :

sqdancefan
A = (1/2)bh
A = (1/2)b(b -5)
2A = b(b -5)
b^2 -5b -2A = 0

Substituting given values, we have
b^2 -5b -2*42 = 0
(b -12)(b +7) = 0

b = 12

The length of the base is 12 m.

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