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For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen, what would be true?

Answer :

 1C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ

1mol C3H8(g) ---- –2200 kJ
2mol C3H8(g)  ----2(–2200 kJ)=-4400kJ

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