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Fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. what volume of oxygen would be produced by this reaction if 7.3 l of water were consumed? also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer :

kenmyna
The   volume  of  oxygen   produced  is  calculated  as  follows
  write    the  equation  for  reaction

  2 F2  +  2  H2O  =  4  FH  +  O2

by  use   of  moles  ratio  of  water  vapor  to   O2   produced  which  is ( 2:1) the  volume   of    O2       =     7.3  x 1/2 =  3.7 L
transitionstate

Answer:

                  4542 L of O₂    (Or)      3.65 L of O₂

Solution:

Calculation 1: If water is given in liquid form.

Step 1: Calculate mass of water as,

                             Density  =  Mass ÷ Volume

Solving for Mass,

                             Mass  =  Density × Volume

                             Mass  =  1.0 g.mL⁻¹ × 7300 mL

                             Mass  =  7300 g

Step 2: Calculate volume of O₂;

The balance chemical equation is as follow,

                                2 F₂  +  2 H₂O    →    4 HF  +  O₂

According to equation,

                36 g (2 mol) H₂O produces  =  22.4 L of O₂

So,

                   7300 g of H₂O will produce  =  X L of O₂

Solving for X,

                       X  =  (7300 g × 22.4 L) ÷ 36 g

                      X  =  4542 L of O₂

Calculation 2: If water is given in gas form.

Then, According to equation,

                      44.8 L of H₂O produced  =  22.4 L of O₂

So,

                         7.3 L of H₂O will produce  =  X L of O₂

Solving for X,

                     X  =  (7.3 L × 22.4 L) ÷ 44.8 L

                     X  =  3.65 L of O₂

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