Answer :
f(k) = -1/2k + 6
You can get this by solving for J and then using f(k) in its place.
You can get this by solving for J and then using f(k) in its place.
we have
[tex]\frac{1}{2} J+\frac{1}{4} K=3[/tex]
Step 1
Solve for J
[tex]\frac{1}{2} J+\frac{1}{4} K=3[/tex]
Multiply by [tex]2[/tex] both sides
[tex]2*\frac{1}{2} J+2*\frac{1}{4} K=2*3[/tex]
[tex]J+\frac{1}{2} K=6[/tex]
Subtract [tex]\frac{1}{2} K[/tex] both sides
[tex]J+\frac{1}{2} K-\frac{1}{2} K=6-\frac{1}{2} K[/tex]
[tex]J=6-\frac{1}{2} K[/tex]
Step 2
Convert the equation in function notation
Let
[tex]f(k)=J[/tex]
[tex]f(k)=6-\frac{1}{2} K[/tex]
[tex]f(k)=-\frac{1}{2} K+6[/tex]
therefore
the answer is
[tex]f(k)=-\frac{1}{2} K+6[/tex]