Answer :

MrGumby
f(k) = -1/2k + 6

You can get this by solving for J and then using f(k) in its place. 
calculista

we have

[tex]\frac{1}{2} J+\frac{1}{4} K=3[/tex]

Step 1

Solve for J

[tex]\frac{1}{2} J+\frac{1}{4} K=3[/tex]

Multiply by [tex]2[/tex] both sides

[tex]2*\frac{1}{2} J+2*\frac{1}{4} K=2*3[/tex]

[tex]J+\frac{1}{2} K=6[/tex]

Subtract [tex]\frac{1}{2} K[/tex] both sides

[tex]J+\frac{1}{2} K-\frac{1}{2} K=6-\frac{1}{2} K[/tex]

[tex]J=6-\frac{1}{2} K[/tex]

Step 2

Convert the equation in function notation

Let

[tex]f(k)=J[/tex]

[tex]f(k)=6-\frac{1}{2} K[/tex]

[tex]f(k)=-\frac{1}{2} K+6[/tex]

therefore

the answer is

[tex]f(k)=-\frac{1}{2} K+6[/tex]

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