1) First one is a line f(x)=2x+1. It has y-int. (0,1), and second point, for example, (1,3)
2 points for line (0,1) and (1,3)
2) Second one is a parabola g(x)=x²+2x-8.
In the vertex form it looks like
g(x) =x²+2x+1-1-8=(x+1)²-9
g(x)=(x+1)²-9 - parabola in the vertex form. Vertex is (-1,-9)
Another point of the parabola can be found from the equation g(x)=x²+2x-8.
It is y-int. x=0, g(0)=-8, so point on the parabola is (0,-8)
For parabola Vertex (-1,-9) and point (0,-8)
3) Solutions are (-3,-5) and (3,7).
