Answer :

 1)  First one is a line f(x)=2x+1. It has y-int. (0,1), and second point, for example, (1,3)
2 points for line (0,1) and (1,3)

2)  Second one is a parabola g(x)=x²+2x-8.
In the vertex form it looks like
g(x) =x²+2x+1-1-8=(x+1)²-9
g(x)=(x+1)²-9 - parabola in the vertex form.     Vertex is (-1,-9)
Another point of the parabola can be found from the equation  g(x)=x²+2x-8.
It is y-int. x=0, g(0)=-8, so point on the parabola is (0,-8)

For parabola Vertex  (-1,-9) and point (0,-8)

3) Solutions are (-3,-5) and (3,7).

${teks-lihat-gambar} mkryukova19

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