Answer :
[tex]\ln x+2\ln y-\ln z=\ln x+\ln y^2-\ln z=\ln\dfrac{xy^2}{z}\\\\Used:\ln a+\ln b=\ln(a\cdot b}\\\\\ln a-\ln b=\ln\dfrac{a}{b}\\\\n\ln a=\ln a^n[/tex]
Answer:
ln [tex]\frac{xy^{2} }{z}[/tex]
Step-by-step explanation:
just took the test :D
hope this helps! don't forget to be amazing!!
