Answer :
[tex]\text {Area of triangle = } \dfrac{1}{2} \text{ab} \sin \text{c}[/tex]
[tex]\text {Area of triangle = } \dfrac{1}{2} (10)(24) \sin (20 \textdegree)[/tex]
[tex]\text {Area of triangle = } 41.0 \text{units}^2[/tex]
[tex]\text {Area of triangle = } \dfrac{1}{2} (10)(24) \sin (20 \textdegree)[/tex]
[tex]\text {Area of triangle = } 41.0 \text{units}^2[/tex]