Answer :
we are given
center=(-1,6)
radius=3
now, we can use standard equation of circle
[tex] (x-h)^2+(y-k)^2=r^2 [/tex]
where
center=(h,k)
radius =r
so, we get
center=(h,k)=(-1,6)
[tex] h=-1,k=6 [/tex]
radius =r=3
[tex] r=3 [/tex]
now, we can plug these values
and we get
[tex] (x+1)^2+(y-6)^2=3^2 [/tex]
[tex] (x+1)^2+(y-6)^2=9 [/tex]
so, option-D............Answer