Answer :
For this case we have the following variables:
x = the number of wing servings
y = the number of burgers
We write the system of equations:
"Sara knows that at least 4 of her friends want wings":
x> = 4
"Sara must spend less than $ 45.00":
6x + 3y <45
Answer:
Sara could use the following system of inequalities to determine how many of each kind of food She can serve:
6x + 3y <45x> = 4
x = the number of wing servings
y = the number of burgers
We write the system of equations:
"Sara knows that at least 4 of her friends want wings":
x> = 4
"Sara must spend less than $ 45.00":
6x + 3y <45
Answer:
Sara could use the following system of inequalities to determine how many of each kind of food She can serve:
6x + 3y <45x> = 4
Answer:
The required inequalities are [tex]x\geq 4[/tex] and [tex]6x+3y<45[/tex].
She can serve 4 wings and 6 burgers, so that she spend less than $45.
Step-by-step explanation:
Consider the provided information.
Wings cost $6.00 per serving and burgers are $3.00 each.
x represents the number of wing servings and y represents the number of burgers.
Sara knows that at least 4 of her friends want wings.
Thus [tex]x\geq 4[/tex]
Sara must spend less than $45.00
[tex]6x+3y<45[/tex]
Hence, the required inequalities are [tex]x\geq 4[/tex] and [tex]6x+3y<45[/tex].
Now find how many of each kind of food Sara can serve.
If she serve 4 wings:
[tex]6(4)+3y<45[/tex]
[tex]3y<45-24[/tex]
[tex]y<7[/tex]
She can serve 4 wings and 6 burgers, so that she spend less than $45.
Similarly, She can serve 5 wings and 4 burgers, she can serve 6 wings and 2 burger or she can serve 7 wings.