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A long distance runner starts at the beginning of a trail and runs at a rate of 6 miles per hour. Two hours later, a cyclist starts at the beginning of the trail and travels at a rate of 16 miles per hour. What is the amount of time that the cyclist travels before overtaking the runner?

Answer :

musiclover10045
the time for the bike = x
the time for the runner = x+2 ( started 2 hours  before bike)

runners speed = 6, bike speed = 16

so you have 6(x+2) = 16x

distribute the left side:

6x +12 = 16x

subtract 6x from each side:

12 = 10x

divide both sides by 10 
x = 12/10
x = 1.2 hours 

1 hour = 60 minutes
1.2 x 60 = 72 minutes

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