1. Use the given circle. Find the length s to the nearest tenth

A. 3.1 in.
B. 15.7 in.
C. 31.4 in.
D. 5.0 in

2. He draws a tile, replaces it, and draws another tile. What is the probability he will draw a blue tile on both draws?

A. 2/35
B. 1/9
C. 16/225
D. 2/21

1. Use the given circle. Find the length s to the nearest tenth A. 3.1 in. B. 15.7 in. C. 31.4 in. D. 5.0 in 2. He draws a tile, replaces it, and draws another class=
1. Use the given circle. Find the length s to the nearest tenth A. 3.1 in. B. 15.7 in. C. 31.4 in. D. 5.0 in 2. He draws a tile, replaces it, and draws another class=

Answer :

calculista
Part 1) Find the length s to the nearest tenth

we know that
[length of a circumference]=2*pi*r
for r=3 in
[length of a circumference]=2*pi*3------> 18.84 in

if 2*pi radians (full circle) has a length of------------> 18.84 in
 (5*pi/3) radians------------------------------> x
x=(5*pi/3)*18.84/(2*pi)--------> x=15.7 in

the answer Part 1) is 
15.7 in

Part 2) What is the probability he will draw a blue tile on both draws?

we 
have a bag of 5 red tiles, 3 yellow, 4 blue and 3 green
total tiles -----> 15

4 blue out of 15
1st draw is 4/15 
2nd draw is 4/15
(4/15)*(4/15)-----> 16/225

the answer Part 2) is
16/225 

Answer:

number 2. c. 16/225

Step-by-step explanation:

i took the exam

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