Answer :
question A
the theoretical yield of Ac is calculated as follows
calculate the moles of AB = mass/molar mass
=41 g/75 g/mol = 0.55 moles
2AB +C2 = 2AC + 2B
by use of mole ratio between AB : AC which is 2:2 or 1:1 the moles of AC is also 0.55 moles
theoretical mass is therefore = moles x molar mass
= 0.55 x 60 = 33 grams
question B
THe % yield = actual yield/theoretical yield x 100
= 16.5g/33 g x100 =50% of AC
the theoretical yield of Ac is calculated as follows
calculate the moles of AB = mass/molar mass
=41 g/75 g/mol = 0.55 moles
2AB +C2 = 2AC + 2B
by use of mole ratio between AB : AC which is 2:2 or 1:1 the moles of AC is also 0.55 moles
theoretical mass is therefore = moles x molar mass
= 0.55 x 60 = 33 grams
question B
THe % yield = actual yield/theoretical yield x 100
= 16.5g/33 g x100 =50% of AC