Answer :
Using probabilities of independent events, it is found that:
The probability of spinning a prime number and not flipping heads is 0.3.
A probability is the number of desired outcomes divided by the number of total outcomes.
If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each event happening, that is:
[tex]P(A \cap B) = P(A)P(B)[/tex]
In this problem:
- The spinner and the coin are independent.
- The spinner has 5 sides, 3 of which are prime, hence [tex]P(A) = \frac{3}{5}[/tex]
- The coin has 2 sides, one of which is tails(not heads), hence [tex]P(B) = \frac{1}{2}[/tex]
Then:
[tex]P(A \cap B) = P(A) \times P(B) = \frac{3}{5} \times \frac{1}{2} = \frac{3}{10} = 0.3[/tex]
The probability of spinning a prime number and not flipping heads is 0.3.
A similar problem is given at https://brainly.com/question/24174994