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A rabbit has found some cone-shaped carrots and wants to hide them in her cylindrical rabbit hole. If the carrots have the same base (at their thick end) diameter as the hole does and are also the same height as the rabbit hole, how many carrots will fit in the hole? [V = πr2h] A) 2 carrots. B) 3 carrots. C) 9.4 carrots. D) π carrots.

Answer :

Cathenna

[tex]volume \: of \: cone = \frac{1}{3} \pi {r}^{2} h \\ volume \: of \: cylinder = \pi {r}^{2} h \\ no. \: of \: carrots \: that \: will \: fit \: in \: the \: cylinder = \frac{volume \: of \: cylinder}{volume \: of \: cone} \\ = \frac{\pi {r}^{2}h }{ \frac{1}{3} \pi {r}^{2}h } \\ = \frac{1}{ \frac{1}{3} } \\ = 3 \: \: \: \: \: (ans)[/tex]
Ans: option B) 3 carrots.

Hope this helps!
B) is the correct answer on USAtestprep

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